If a.b=a.c then how a is perpendicular to b-c?
a.b=a.c
Therefore, a.b-a.c=0
a.(b-c)=0
|a|*|b-c|* cos θ=0
cos θ=0
Or angle is 90 degress.
Hence a will be perpendicular to b-c
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a.b=a.c
Therefore, a.b-a.c=0
a.(b-c)=0
|a|*|b-c|* cos θ=0
cos θ=0
Or angle is 90 degress.
Hence a will be perpendicular to b-c
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