if mod a+b =mod a-b then prove ais perpendicular to b
Answer (1)
16th Mar, 2020
Hi Shubhangi,
|a+b|=|a-b|
Squaring both sides:-
|a+b|^2=|a-b|^2
|a+b|^2 - |a-b|^2=0
4 *a*b=0
a*b=0
Now,here we will apply projection theorem
cos@=a*b/|a||b|
now here a*b=0,therefor
cos@=0 which means angle between a and b is 90 degree.
Hope this will help,please feel free to ask if you have any further queries.
Thank You.
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