870 Views

If V = x^2 - 5x + 4 , find the acceleration of the particle when velocity of the particle is zero

gaikwadomkar124 12th Aug, 2020

Answer (1)

Prabhav Sharma 12th Aug, 2020

Hello,

Velocity of the particle is given by, v = x^2 - 5x + 4 (Given)

Therefore, acceleration = dv/dt = d/dt(x^2 - 5x + 4)

= 2x * dx/dt - 5 * dx/dt

= 2x * v - 5 * v [We know, dx/dt = v]

When v = 0, Acceleration will be = 2x * 0 - 5 * 0 = 0

Therefore, Acceleration of the particle is 0 when velocity of the particle is 0 (Answer)

Hope it is clear!

Share

Facebook Copy Link

More

Comments (0)

Related Questions

A particle moves along X axis. The velocity of the particle as function of x is v^2 = 12x - 3x^3 ( in SI ) . Find velocity of particle at the instant when acceleration is 1.5ms^-2

3461 Views

A particle executes SHM of amplitude A. At what positions of its displacement (X) will its,(1) velocity be zero and maximum and (2) acceleration be zero and maximum?.

1921 Views

The motion of a particle is express by the equation X=5t -9,Y= 2 cos 3t ,Z = 2sin3t , calculate the velocity , acceleration of the particle.

1017 Views

a particle starts with some initial velocity and constant acceleration in some direction.distance travelled by the particle in first 4 sec is 100 m and in next 4 sec is 140m. find velocity of the particle at 6 second?

175 Views

A particle is projected with velocity V along x-axis. A damping force is acting on the particle which is proportional to the square of the distance from the origin. i.e, ma = -x 2 . The distance at which the particle stops

1066 Views

Link Copied

The question have been saved in answer later, you can access it from your profile anytime. Access now

Thanks! Your report is submitted, the author will be informed about it

Download Careers360 App

All this at the convenience of your phone

Regular Exam Updates
Best College Recommendations
College & Rank predictors
Detailed Books and Sample Papers
Question and Answers