In neet 2018 69.402 percentile equals how much mark please i need it
Dear Sir / Ma'm, percentile is calculated by taking your marks multiplied by 100 and dividing the whole thing by the highest mark obtained by the top ranker. Going by the trend of 2017, a student whose All India score was 192 got a percentile of 67.677. These are subject to change as the highest marks also varies each year. You can expect a score of around 190-200. Again these are mere assumptions and are subject to change.
Before jumping onto your question.
Let's go step by step.
Your percentile = 69.402 which means about 69.402% of the total Examinees are behind you. Or 30.598% of the total Examinees are ahead of you.
Total number of Examinees = about 15.6 lakhs.
Therefore, your AIR = (30.598/100)x15,60,000
Which stands at, 4,77,329.
As per the statistics of 2018, a rank as such would have corresponded to a marks of 151-160 and a same rank in 2017 gave a score in the range of 141-150.
Since 2019 paper was on a easier aspect, we would take into consideration that the same marks would give you a +40 score
Thus your score might just be near to 200.
Hope this helps.
All the Best !
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