Is 91.507919% will make me eligible for jee advanced.And how much marks may fetch me 97% and above, what all should I practice for this??

hii,

NTA doesn't declared anything about JEE main cutoff so nothing can be said with 100% surity.although experts from well recognised Institutions has said that the cutoff of JEE main will be 85 percentile or more.

so according to this you will be selected for JEE Advance.

I can not tell your total marks now.but your approximately rank can be calculated by the formula =[ (100- NTA percentile score ) X 874469 /100.]

is 74260.

also you can predict your rank via using the given link-

https://engineering.careers360.com/jee-main-rank-predictor

you should only focus on JEE advance Preparation.

you should solve numericals as much you can.solve previous year qustion papers.It will be very usefull for you.

here i am enlisting the name of some books ,you should practice them-

PHYSICS:

• NCERT Textbooks
• Concepts of Physics Vol I and II by H.C. Verma (Highly Recommended)
• Fundamentals of Physics by Halliday, Resnick & Walker
• Problems in General Physics by I.E. Irodov
• IIT Physics by D.C. Pandey
• Problems in Physics by S.S. Krotov

CHEMISTRY:

• NCERT Textbooks
• Organic Chemistry – O. P. Tandon
• Organic Chemistry – Peter Sykes
• Organic Chemistry – M. S. Chauhan
• Organic Chemistry – Morrison and Boyd (This book covers a lot of topics with extensive detail. Make sure you highlight what is important before you proceed if you have a time constraint)
• Physical Chemistry – O. P. Tandon
• Concise Inorganic Chemistry – J. D. Lee
• Modern Approach to Chemical Calculations – R. C. Mukherjee (for practice)

MATHEMATICS:

• Maths XI & XII by R.D. Sharma
• Objective Mathematics for JEE Main & Advanced and Other Engineering Entrance Examinations by R.D. Sharma
• Trigonometry & Geometry: – Plane Trigonometry Part 1 by S.L. Loney
• Co-ordinate Geometry: – Plane Co-ordinate Geometry by S.L. Loney
• Algebra: – Higher Algebra by Hall and Knight
• Calculus: – Problems in Calculus of One Variable by I.A. Maron
• Differential Calculus by A. Das Gupta.
• Course in Mathematics for IIT-JEE by Tata McGraw-Hill publications. [practice]

hope you understand

thank you.

Hii aspirant, congratulations for scoring  91 percentile.Having 91.507 percentile in jee mains, your general rank will be in between 75000 to 80000. With this rank you will definitely qualify for jee advanced 2019.

Predicting marks with help of percentile is  difficult because it depends on the marks of the candidates who gave exam on same day,the percentile is calculated merely with the help of these marks on that day.

Hope you understands.

Hello.

The official Jee Advanced cutoff will be released after the exam in April. The expected cutoff is about 85 percentile, so you will most likely be eligible for the exam. The percentile score is released relative to the performance of all the candidates who have attempted the exam. So, it's quite difficult to give you an accurate estimate of your raw score to get a specific percentile score.

Hope this helps.