Is it possible to get NIT with 88.89 percentile?
89.89 percentile could fetch you a rank around 103425-116265.now these are based on previous year analysis .As of now its tough to say because the analysis and also cutoffs change every year due to many factors like total students appearing for exam,difficulty level of paper etc..considering you from general category you have very low to no chances to fetch seat in government colleges nits or iiits, however you can try to fetch seat in private colleges or universities.or you can try the state b tech colleges using jee main percentile. you see the last year qualifying cutoff was 90 percentile for gen category it was not admission cutoff.you need better percentile to fetch seat. work hard for the upcoming jee main sessions..for more information to get a personalised report on what all chances you have for your rank refer to: https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer
hope this helps,
thankyou.
Hello,
According to your percentile your Overall Rank will be 113655 - 127765. You have chances of getting seat in NITs and good Private Engineering Colleges. This analysis is based on previous year's cut-offs.
You have chances of getting seat in below mentioned NITs.
NIT Goa
NIT Agartala
NIT Rourkela
NIT Meghalaya
NIT Hamirpur
NIT Sikkim
Predict your JEE Mains rank using JEE Mains Rank Predictor. Its prediction is based on previous year's data.
https://engineering.careers360.com/jee-main-rank-predictor
Go through JEE Mains cutoffs using below links. These cut-offs are based on previous year's cut-off trends. So, you have have a look of cut-offs of JEE Mains of various colleges using below links.
https://engineering.careers360.com/articles/jee-main-cutoff
https://josaa.nic.in/Result/Result/currentorcr.aspx
Predict which colleges you can get for your JEE Mains rank using below link. This analysis is based on previous year's opening and closing ranks of various colleges.
https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer
Hope this information helped you.
Best of Luck!!
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