Sin20 sin40 sin60 sin80 =3_16 ,
Answer (1)
Hi firdaus
Here is the answer
sin20. sin 40. sin60. sin80
=> sin60[sin20.sin40.sin80]
=>3/2[sin20.sin(60-20).sin(60+20)]
=>3/2[sin 3(20)/4]
=>3/2[sin 60/4]
=>3/2[3/2*4]
=>3/2*3/8
=3/16
Good luck
Here is the answer
sin20. sin 40. sin60. sin80
=> sin60[sin20.sin40.sin80]
=>3/2[sin20.sin(60-20).sin(60+20)]
=>3/2[sin 3(20)/4]
=>3/2[sin 60/4]
=>3/2[3/2*4]
=>3/2*3/8
=3/16
Good luck
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