Sir, I had a NTA score of 71.22894 in jee main, is I'm eligible for B. Arch..? I'm obc too.

Hello Aspirant
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Our experts team has declared the minimum percentile is 85 to qualify the jEE mains paper 2 exam. This is not an official one just approximately by previous years census they declared.
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Use this formula to predict the rank:
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• Rank Formula = (100 - your total score) X 145386 /100.
• Your expected rank is 41842 by using above formula.

Your rank may differ from the official cutoff and results which were released on the month of April by national testing agency NTA officially.You have to wait for the official results.
if you want to compare with previous years cutoff of b.arch .you can go through the below link:
https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning
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I would like to suggest you that give attempt to April jEE mains paper 2 exam to improve your percentile to get  NIT Colleges. if you get 95+ then you will definitely get top nits.
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If you have any questions further let me know.
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Thank you!!!