Svhedule to prepare in 20 days to crack NEET 2018?

Dear shabnum
Last 20days will be the golden period for you, since you are good with concepts and have solved enough no. of mcqs you need to revise those in last 20days, don't waste time, have self confidence
All the best

There is barely anytime left and all that is expected from you at the moment is to revise whatever you have done all this while.
Don't jump into learning a new concept or reading something that you haven't come across previously.
Keep solving full length test papers, get your doubts clarified and try not to repeat the same mistakes again and again.

Last 20 days should be devoted only to revision. Don't start a whole new topic or book. Also, you must solve as many questions as you can. Solve previous year question papers, mock tests, sample papers. This is very important to increase your problem solving speed.
Revise your notes and key points. Revise formulae of physical chemistry and physics.
Besides all this, remember keeping your cool is very very important in this phase. Spend some leisure time also. So meditation or yoga or any light physical exercise to relax.
Plan well, execute it well and do well.
All the best for your exam.

With only 20 days left for neet i would like to tell you that.

• Solve previous year question papers
• Solve the test papers of your coaching institute again and again
• Solve physics mcqs as much as you can get an idea about your concepts
• Revise ncert throughly and religiously specially for biology and chemistry
• Try to solve the jee main physics to get a further deep insight
• Be relaxed and remain stress free
• Best of luck for neet!!

Hi Shabnam,

CBSE NEET UG exam will be held on May 6, 2018. As you have appeared for your Class 12 boards recently, so it must be safe to assume that you are well acquainted with the concepts of the subjects. However, with less than 1 month for NEET exam, you should definitely have some pointers for yourself. I would suggest you go to this link NEET Preparation Strategy. I hope this would answer your query.