What is the cut off rank to take admission in b.tech cs

The cut-off rank for B.Tech Computer Science (CSE) in India varies greatly depending on the institute, the category of the candidate, and the year. Generally, for top IITs, a rank below 500 in the General category is considered competitive. For NITs, the cut-off can range from 1,000 to 10,000 or higher, depending on the specific NIT and the category. Private and other engineering colleges have a wider range of cut-off ranks.

The cut-off rank for admission to a B.Tech in Computer Science Engineering (CSE) varies significantly depending on several factors. These include the specific college or university, the entrance examination you are considering (e.g., JEE Main, state-level entrance exams like WBJEE, or private university entrance exams), the category you belong to (General, OBC, SC, ST, EWS), and the overall number of applicants and available seats for that particular year.

Generally, Computer Science is one of the most sought-after engineering branches, leading to higher cut-off ranks compared to other disciplines. For top-tier institutions like the Indian Institutes of Technology (IITs), the cut-off ranks for general category students can be within the top few thousand in JEE Advanced. For National Institutes of Technology (NITs) and other well-reputed government and private colleges, the cut-off ranks in JEE Main can range from a few thousand to tens of thousands, again depending on the specific institute and its ranking.

It's important to understand that each institute releases its own set of cut-off ranks after each round of counseling. These ranks are dynamic and can change from year to year based on the factors mentioned earlier. To get a more precise idea, you should refer to the official websites of the specific colleges you are interested in and look at their cut-off ranks from previous years. This will give you a general trend, but keep in mind that the actual cut-off for the current year might be different.