What is the minimum cut off in B-tech

Question

Hi I like B.tech IT course and I like mgr university my cut off is 141.75 pls tell any chance to study in this clg

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Answer 1

Hi Manoj,

TNEA 2019 cutoff is the base imprints required for affirmation in the partaking foundations and the building courses offered by them. In this way, applicants who are looking for affirmation through TNEA need to score more than or equal to cut off discharged by the specialists.

The cut-off imprints required to fit the bill for JEE Advanced 2019 will be discharged after the JEE Main January and April test is finished.

JEE Main 2019 Cut Off for JEE Advanced.

Category JEE Main 2019 Cut Off

Gen EWS 78.2174869

OBC NCL 74.3166557

SC 54.0128155

ST 44.3345172

Take your Physics, Chemistry and Mathematics marks. Partition the material science and science checks by 4 and Divide the Maths mark by 2, Add the 3 outcomes you will get the Engineering Cutoff stamps out of 200.

Good Luck!!