which architecture college can i expect to get with 98.58 percentile
Rank in JEE Main Paper 2 can be calculated by the formula:
Rank = (100-percentile)*(No. of students appeared for the examination)/100
As the no. of students appeared for Paper 2 are 112679, your rank will be around 1600. However as the no. of students in April changes, your rank will change according to that.
With this rank, you have sufficient chances of getting architecture branch in one of the top NITs.
Here are some colleges which you may get with this rank:
- MNIT, Jaipur
- NIT Calicut
- NIT Rourkela
- Some chances in NIT Trichy
Since this is not complete list, use the college predictor through the link given below to get the list of all colleges which you may get based on your percentile:

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