Dear Aspirant,

The formula to convert percentage into rank in Jee main is:

(100-NTA percentile score)*869010/100

Where,

869010- total number of candidates that appeared for JEE

So your expected rank approximately is 86901.

Thank you!!

Hi Jagdish,

Yes, the syllabus of  class11 and 12 together for JEE Main is as follows:-

@Mathematics

• Complex numbers and quadratic equations
• Matrices and determinants
• Sets, relations and functions
• Mathematical induction
• Permutations and combinations
• Mathematical reasoning
• Limit, continuity and differentiability
• Integral calculus
• Three-dimensional geometry
• Differential equations
• Binomial theorem and its

Hello learner,

There are plethora of government colleges in Pune, that offers quality academics with satisfactory fee. I would list the top ranking colleges in Pune along with the fee structure.

• College of Engineering [COEP] - 90,850
• Army Institute of Technology - 1,62,995
• MIT World Peace University [MITWPU] - 3,10,000

Hello,

According to JMI Prospectus 2020-21 (page 35) http://jmicoe.in/pdf19/FINAL_JMI_PROSPECTUS_2020_NEW.pdf you need to fill two separate applications for two different courses. Multiple applications for the same course will be rejected but in your case you are applying for two different courses that is B.Tech and B.Arch so you need to fill

If we calculate your rank with your percentile, it is approximately 96373. The formula is 100-your percentile*no.of candidates who wrote the exam/100. With this rank, it is difficult for a seat in NIT. You should score atleast 95 percentile and more. So you should write July session. To check what

Hello dear

J ee mains paper one is for admission in btech course in various esteem Institutes like NIT, IIIT s and other state College and private colleges. Once you qualify jee mains you will be eligible for jee advanced through which you can take admission in IIT s in

The lockdown might have a big impact on CRL in JEE Mains, specially for those who do not have access to online coaching classes or study material. For these people their studies might have got disrupted to some extent. Feeling low during lockdown and not feeling like studying is only

Rakesh, your rank would be approximately 7212 going by the formula 100-99.17*869010/100 where in 99.17 is your percentile and 869010 is the no.of Candidates who appeared for JEE Mains for January session. For example, if the Candidates appearing for July session go upto 12.00.000 then we use 1200000 instead of

HELLO!!!!!

The JEE Mains examination will be conducted twice a year.For the JEE Mains paper 1 which is conducted by NTA(National Testing Agency) in janauary there are total about 11,18,673 registrations for JEE Mains examination including both B.tech and B.arch.There are about 9,21,261 registered candidates  for b.tech in which only

hey,

no its not mandatory to give  jee main 1 exam to appear in jee main 2 exam ,both exams are for different purpose ,first one is for those who want to take in B.E or Btech whereas paper 2 is for architecture students who wish to pursue B.arch from