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JEE Main Paper 2

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96 Views

I have 84.21 pr in jee main paper 2 my cast is obc I have addmission in nit

Rahul Student Expert 25th Jan, 2020
Hello aspirant,

100 - your total percentile score is the percentage of people ahead of you. 112679 are the number of candidates appeared for January exam.

Rank formula is (100 - your total score) X 112679 /100.

So, based on your percentile score your rank will be around 17000. According,
211 Views

My percentile is 93.8 in b arch.What are my chance of admission in NIITs or some other places.

SAKSHI KULSHRESHTHA 25th Jan, 2020

Rajesh, you can calculate your expected JEE Mains paper 2 rank for the January session using the following formula:

(100-your total percentile) x 112679/100

So with 93.8 percentile, your rank would be around 6986.

Most top colleges in India require a rank of 5000 or below in JEE Mains paper

1247 Views

have scored 82 percentile jee main paper 2 In which NIT will I get admission?

Harshita Gupta 24th Jan, 2020
Hey Khushi,

According to your percentile, your rank will be around 20,282.
You can calculate it using the formula:
(100 - your total score) X 112679/100.

Here, 112679 is the number of candidates who appeared in JEE main paper 2. This is just overall rank and category specific ranks are
53 Views

my percentile for mains paper 2 is 68.023 what is my rank

Pachigolla Hemanth 24th Jan, 2020

Hello Mulange vishnu prasad,

you can predicate your rank by using the formula.,

(100-your percentile)*no.of students wrote the exam/100,for the january exam total no of students are 112679,by this you can find your rank.

Then you rank is to be 36301

And also rank will be changed after the April

419 Views

I get 75 percentile in jee main paper 2.Can I get a good government college?

Pachigolla Hemanth 24th Jan, 2020

Hello Devanshi Gupta,

According to the previous data,if you get 75 percentile in the JEE mains paper 2,then you have very less change to get seat in the colleges.So it is better to write the exam again in the month of April . And also make a plan for the

97 Views

My daughter got 85.37 NTA score in JEE main paper 2. we are belonging to OBC. what are her position in NITs. is there any chance. What are the other possibilities.

Sameer Wagh 24th Jan, 2020
Mam Frankly speaking tere no chance of getting Nit because Obc category need minimum of 96 percentile to get good clg and for nit and jj she  need 99 percentile so its difficult to get her in nit
134 Views

my jee main paper 2 percentile is 48.78 and Im from general category which college will I get seat for b arch

SAKSHI KULSHRESHTHA 24th Jan, 2020

Manya, you can calculate your expected JEE Mains paper 2 rank for the January session using the following formula:

(100-your total percentile) x 112679/100

So with 48.78 percentile, your rank would be around 57714.

According to your rank, it will be difficult to get a seat in the top colleges.

169 Views

My Jee main paper 2 percentile is 89.824. I am from SC category.Which NITs can I get?

Shubham Dhane 24th Jan, 2020

Hello,

We can use the below formula to calculate your approximated rank

100 - your total percentile score is the percentage  of people ahead of you. 112679 are the number of candidates appeared for January exam.

So rank formula is (100 - your total score) X 112679 /100.

Your predicted

47 Views

sir,i got 87.9percentile in b.arc.,i m general category female from telangana.can i got admission?

Sudarshan kumar 24th Jan, 2020

Hi Sreeja,

Your percentile is not good enough to get into any NITs or IIITs even in female quota. You should prepare more harder to get better percentile then this to get into NITs or IIITs or any other good government college.

You should also Check cutoff by yourself at

210 Views

my jee main paper 2 percentile is 94.3% and i belong to obc male what is my rank??

Vishwaksen Gouda Student Expert 24th Jan, 2020
Hello abhi nav,
As you have secured 94.3 percentile in the jee main paper 2 it is good
To calculate the rank for B.Arch:
100 - your total percentile score is the percentage of people ahead of you. 112679 are the number of candidates appeared for January exam.
So rank
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