Here I am providing you the KJSCE MUMBAI 2018 cutoff .All rank metioned here are All India Merit No. and all scores are JEE Main 2018 Paper-1 Scores.

Branch                             Cutoff rank(scores)

Computer                           922(150)

Electronics and 

Telecommunication              2075(120)

Electronics  Engg.                 2498(113)

Information Tech.                1465(134)

Mechanical Engg.                 606(164)

Hello,

the cutoff for CSE is in 4 digits at KJSCE. for previous year the first round cutoff was 607 for CSE and 3rd round cutoff was 922. It is same for other branches too. You have to look for other college where you can take an admission. In this percentile you can't get KJ Somaiya.

LOOK for other college where you can pursue the course satisfiedly.

you can get more details cutoff of KJSCE from the link :- https://www.careers360.com/colleges/kj-somaiya-college-of-engineering-mumbai

Hope it helps!

Hi,

All college admissions are done as per the rules and regulations of Competent Authority, Directorate of Technical Education/State CET Cell/ Admission Regulatory Authority,Government of Maharashtra through Centralized Admission Process.

Soon after the declaration of  MHT-CET result,  the Competent Authority invites applications from eligible students for first year Engineering, prepare merit list and provisionally allot the admission through Centralized Admission Process.  As per the allotment, College admit the candidates after verifying their original documents,  collect requisite fees and confirm their admission.

Hi there .

Among the colleges you mentioned , cummins college is the best . Because it have high placement ratio and instead of MIT WPU and others , these are private colleges . You must surely seek for Cummins college without any doubt . 

Hope this was helpful. 

Hey Vinit!

Hope you are doing well.

KJSCE offers B.Tech in 5 specializations. The candidates aspiring to pursue B.Tech must have passed HSC (10+2) level examination along with a valid MHT-CET/JEE Main score.

MHT-CET is a state level offline entrance examination conducted in Maharashtra and JEE Main is an all India level examination to be conducted in offline and online mode.

Admission will be done through Centralized Admission Procedure (CAP) conducted by DTE.

The basic eligibility criteria for admission in KJSCE is that a student must have passed standard XII (10+2) level examination with Physics and Mathematics as compulsory subjects along with Chemistry/Biology/technical/vocational subject  OR Diploma in Engineering and Technology with minimum 50% marks (45% for SC/ST candidates from Maharashtra Only) from a recognized university.

You can check  previous years' JEE Main cutoff for KJSCE here:

https://www.collegepravesh.com/cutoff/kjsce-mumbai-cutoff-2018/

Hope this helps.

Good luck!

Hello,

As per the cutoff released for various categories, following is the cutoff designated to various category reservation to qualified to JEE advanced from the JEE mains: 

• General category -89.7548849
• General ews-Crl :78.2174860
• Obc-ncL:74.3166557
• Sc: 54. 0128155
• St: 44.3345172
• Pwd: 0.11371730

All these numbers are in terms of percentile. Anyone securing higher than the fixed cut off percentile of their category is eligible for JEE advanced. 

I hope this helps.