Hello Zishan, If you are local residents of jharkhand then you will eligible to get Home state Quota in NIT Jamshedpur as Jamshedpur lies in jharkhand.

It's difficult to tell you the exact rank or score to get into NIT Jamshedpur or other NITs, IIITs & GFTIs.

Last year closing Cutoff rank for  CSAB- Round 2 Home state OBC Candidate was 41.222 in NIT Jamshedpur Mechanical Engineering which held after the completion of first 7 rounds of JOSSA.

If you have any queries regarding this then you can ask in the comment section.

hi,

see as per your percewntile your probable rank will be around 13000, as per last year cutoff you have chances in nit jamshedpur for following stream,

Metallurgical and Materials Engineering

Production and Industrial Engineering

however right now jee main april session exam is yet to held, and if the number of candidates increased this time it will have effect on your percentile and cutoff scores. you may follow the below link to know about previous years cutoff for nit jamshedpur.

https://engineering.careers360.com/articles/jee-main-cutoff-for-nit-jamshedpur

Hello rajesh kumar,

Sorry, there is no chance to get admission in NITs jamshedpur or any NITs with this percentile. You can try to another good engineering colleges. I would suggest you that you should reappear for jee mains April session.

I hope this helpful for you.

Best wishes!!

• You have this year's JEE MAINS Exam in January or April.
• You should atleast have 75% aggregate score in your Board exams.
• You in the list of the shortlisted candidates( top 2,50,000 students in JEE MAINS)

Hi,

The chances of getting a seat in nits depend on your rank obtained in jee main exam.

Though it is difficult to predict actual rank or JEE advanced qualify marks. your expected rank can be calculated by using the formula

100 - your total percentile score is the percentage  of people ahead of you. 869010 are the number of candidates appeared for Jan exam.

So rank formula is

(100 - 97.78) X 869010 /100.

So using above formula your expected overall rank would be around 19,292.

If the number of candidates for April exam increased to 1200000 then your final rank shall be around  (100 - 97.78) X 1200000/100 that is 26,640

The seat which you would expect to get depend on many factors like number of candidate applied, category, difficulty level of exam etc.etc.it varies from year to year.

You can check the previous years cutoff with rank from the link to have more comprehensive idea.

https://engineering.careers360.com/articles/jee-main-cutoff-for-nit-jamshedpur

Your EWS category rank would be different than the overall rank. The previous years trends shows that there are decent chances that you can get a seat at nit Jamshedpur.

You can check the college predictor link to check other colleges for you can expect admission

https://engineering.careers360.com/jee-main-college-predictor

Hope this helps. All the best.

Your rank can be predicted by using the formula, (100-your total percentile)*869010/100. In your case, your approximate rank would be  53009. Let's say the number of candidates for April exam increased to 12,00,000 then your final rank shall be (100 - your total score) X 12,00,000/100.

In 2019, the cut offs for NIT Jamshedpur, for female OBC Home State Candidate have been as follows:

Civil Engineering: 16612

CSE: 8148

Electrical: 12083

ECE: 11607

ME: 14011

Metallurgical: 16769

Production: 15011

Now these are 2019 cut offs and cut offs change every year depending on various factors such as Total no. of seats available, difficulty of the exam, previous years trends, no. of Candidates appearing for the exam and no. of Candidates applying for a course. So anything less than 95 percentile would be difficult for a seat in Home State NIT. But if you want to check the closing ranks of other NITs, please visit our page: https://engineering.careers360.com/articles/jee-main-cutoff

Now to predict colleges, please use our college predictor: https://engineering.careers360.com/jee-main-college-predictor

Hi dear,

You have got 88.913 percentile in JEE main that means your rank should be around 96347. You can also calculate your rank as

Rank=(100-your percentile)×869010÷100

You sc category rank will be around 3k-3500. You will get a seat in NIT Jamshedpur. You have to mention your state for information about branch.

Hope it helps.