Hello!

Vel Tech multi Tech college was established earlier than Saveetha Engineering college. There are more courses available in Saveetha because that is a Deemed University, whereas Vel Tech Multi Tech don't offer that many courses as they are private college. Saveetha's placements and packages are far better than Vel

Hi Student

Candidate who has passed Senior Secondary Certificate (10+2) examination of Board of School Education Haryana, Bhiwani with 45% marks in aggregate (OR) Any other examination recognised by this University as equivalent thereto.

I am providing link where you can get brochures and other information on BA English in

hello,

I'm going to keep this answer brutally honest and say that 60% is the basic eligibility for admission in that college. But your seat also depends on the cut-off that the college takes out. As of yet, the cutoff is not out and you can call the college authorities

Hey Rajesh

The eligibility criteria for getting admission in BA hons Economics is calculated by taking your best of four marks in consideration (1 language + 3 elective).

Mathematics is a compulsory subject, that is, the candidate must have studied and passed mathematics at the qualifying exam.

Thank you

Hi,

If you are referring to admission merit list to B.Arch in CEPT then it hasn't been declared yet. Candidates are advised to regularly visit the official website of the college for further updates. The official website of the college is given

https://cept.ac.in/

All the best.

Hello Aspirant,

I'll compare both the colleges on basis of their placements, courses offered, fee structure, infrastructure and etc... Based on this  you can choose one among those two.

Chennai institute of technology offers total 15 courses in that 10 for B.tech. Coming to Placements 23 LPA is the highest

Hello,

Saveetha engineering college, chennai is a AAA rated private college. It has a NAAC accreditation of grade A and is a autonomous college. Total faculty is 374 and 4347 students enroll at this college. They provide various branches in engineering  like entc, mechanical, computer science, artificial intelligence, chemical engineering,

Hello Student,

sec(x)=1/cos(x)

Also, cos(A+B)=cosA*cosB - sinA*sinB

Using these two,

sec(240)=1/cos(240) = 1/cos(pi+60)= 1/(cos180*cos60 - sin180*sin60)

Here, cos 180 = -1, sin180 = 0.

Hence,

the value would be 1/ (-cos60) = 1/(-1/2) = -2.

Hope this answers your question. This can also be done directly with the help of