Hi there,

Hope you are doing fine.

To know about the colleges that you can get at this rank, you can visit the official  website of the josaa and the csab counselling authority and then check the previous year cutoff and the opening and closing rank to know about the

SASTRA University's School of Law offers 60 seats each in its three undergraduate law programs: BA LLB (Hons.), B.Com LLB (Hons.), and BBA LLB (Hons.). Admission is based on CLAT scores and fulfilling other eligibility criteria.

Hi

hope you doing well

Your chances of getting CSE at SASTRA University with 91.4 percentile in JEE Mains and 84.6% in CBSE board are moderate but not guaranteed, as admission to SASTRA is highly competitive , especially for the CSE branch.

Sastra admission criteria depends on the more weight

Hello,

To determine your eligibility under Stream 1, you would need to know your actual JEE Main score (not percentile), as the combined score calculation requires it. Without this, it's challenging to compute your exact SASTRA Rank for Stream 1.

For Stream 2, with a 98.1% in your Class 12

With an AIR of 11,300 in CLAT and your excellent predicted score of 580+/600 in your 12th boards , you have a good chance of getting admission to SASTRA University for the BA LLB program, though admission is not solely based on CLAT. SASTRA University has its own admissions process

Correct Answer: evaluation

Solution : The correct answer is the first option, i.e., evaluation.

It refers to the assessment or examination of something to determine its effectiveness, worth, or success. In the context of the sentence, indicators are identified to be used in the evaluation of the success of policies.

Correct Answer: 2

Solution : Given: $a^{3}+\frac{1}{a^{3}}=2$
⇒ $a^{3}+\frac{1}{a^{3}}=2$
⇒ $a^{6}+1 =2a^3$
⇒ $a^{6}-2a^3+1=0$
⇒ $(a^3-1)^2=0$
$a = 1$, the above equation is satisfied.
Now putting $a = 1$, in the equation, we get
$\frac{a^{2}+1}{a} = \frac{1^{2}+1}{1} = 2$
Hence, the correct answer is 2.