hi I got 632 in neet general category kya lady harding mai admission mil sakta h I am Delhi domicile

If are  you interested takings admission in NEET Mbbs-college contact this number 7208540286  for counseling management seat or NRI seat directly meeting in college

Hi

It's quite difficult to predict that whether you will get  seat or not as  cut off marks for medical colleges keeps changing every year  depending upon various factors like  number of students that appeared in the exam, kind of marks obtained by them , toughness level of the examination etc.

But when we go through previous data then it suggests that with 632 marks you hold good chance to get seat in Lady Hardinge Medical College, New Delhi

For example,
In neet 2019,  613 marks  for general category got a seat in Lady Hardinge Medical College, New Delhi under Delhi state quota

To get the list of colleges in which you have chances, you can go through our college predictor at

https://medicine.careers360.com/neet-college-predictor?icn=QnA&ici=qna_answer

It gives you a personalized report with top college in which you have chances for admission , with the help of predicted colleges you can make better choice while filling your choices of colleges during your counselling

Thankyou

In 2019, under State Quota, 613 marks secured a seat in Lady Hardinge Medical College under General Category. That was the cut off. With a score of 632, your rank might be approximately between 1809-2570 . This is an expected rank range: https://medicine.careers360.com/articles/neet-result-marks-vs-rank . With a score of 632, you do have decent chances for a seat in LHMC.

Having said that, this is based on 2019 data and cut offs change every year. Cut offs change every year depending on various factors such as no.of Candidates appearing for the exam, no.of Candidates qualified, top NEET score and difficulty of the exam. For a complete list of colleges that you may have a shot at, please use our College predictor: https://medicine.careers360.com/neet-college-predictor?icn=QnA&ici=qna_answer