what the jee mains cutoff for cse

Hello aspirant,

JEE Main Cutoff 2025 will be announced by NTA on the official website, jeemain.nta.nic.in. Candidates may view the JEE Main Cutoff 2025 by category here. The minimum score needed to be eligible for the exam is the JEE Main Cutoff 2025. Those planning to take the JEE Main 2025 exam should review the anticipated JEE Main Cutoff 2025 per category. Candidates can anticipate the JEE Main Cutoff 2025 for the General category to be 93.24 and for OBC for CSE to be 79.67, based on the cutoff from the previous year.

For complete information, you can visit our site through following link:

https://engineering.careers360.com/articles/jee-main-cutoff

Thank you

Hi,

The JEE Main cutoff is the minimum mark required to pass the JEE Mains exam to get admission to the National Institute of Technology. The expected cutoff for computer science and engineering course General category is 95+, 83+ for OBC, 85+ for EWS, 65+ for SC, and 50+ for ST.

The JEE Main 2025 exam is being conducted on January 22 to 30 january, 2025.

Hope this information will help you

Hello,

The JEE Main 2025 cutoff for Computer Science Engineering (CSE) admissions varies across institutions and categories. While exact cutoffs will be released after JoSAA counselling, expected trends based on previous years are:

• Top NITs : General category candidates may require a rank between 1,200 to 5,000.
• Mid-tier NITs : Ranks around 5,000 to 12,000 are typically needed.
• Top IIITs : Expected ranks range from 1,000 to 10,000.
• Other IIITs : Ranks between 10,000 to 25,000 are common.

These figures may vary based on factors like exam difficulty, number of applicants, and seat availability.

Hope it helps !