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163 Views

mera nta score 17.53h mera kya rank h or mujhe kya score milega

Shudhanshu Gupta Student Expert 22nd Jan, 2020
Hello.
It is quite difficult task to numerate your marks from your rank or percentile again it is difficult task to neumerate your actual rank but you can calculate your approximate rank by using the below formula:
(100-your total percentile score)*869010/100.
Let's suppose the number of candidates appeared in the
69 Views

can I get admission in dhirubhai ambani gandhinagar ?my jee score 76.46

Shudhanshu Gupta Student Expert 22nd Jan, 2020
Hello.
Your approximate rank can be calculated by using the below formula:
100-your total percentile score)*869010/100.
let suppose the number of candidate appeared for the April session exam increased to 12,00000.
Then your rank will be calculated by the modified formula:
(100-your total percentile score)*12,00000.
In the second situation your
88 Views

got 68 score in jee 2020 can I got VNIT collage in this percentage ?

manisha.gupta 18th Jan, 2020

Hello Aspirant,

The exact prediction would be difficult regarding your admission possibilities based on your percentile. But based on this percentile the chances seems less to qualify the exam or get a seat in VNIT or any other NIT, IIIT & GFTI.

You can try for the state level counselling.

85 Views

I have an nta score of 30.38 in jee mains 2020 what are the possibilities of getting NIT

Shudhanshu Gupta Student Expert 22nd Jan, 2020
Hello.
You didn't mention your state and category so it is quite difficult to predict your chances of getting admission in NIT.
Still I am considering for all possibility.
You can calculate your approximate rank by using the below formula :
(100-your total percentile score)*869010/100
Let suppose if the number
35 Views

I got 47.033 as nta score for 7th Jan shift 2 paper 2020 then what is my percentile and is the score enough to take admission in any NIT

SAKSHI KULSHRESHTHA 28th Jan, 2020

Baidurja, NTA score is the same as percentile. So your percentile will be 47.033; this means that your performance was better that 47.033% of the total candidates.

You can calculate your approximate rank for JEE Mains using your percentile through the following formula:

(100-your total percentile) x 869010/100

So with

690 Views

is 20 nta score a good score in jee main 2020 8 Jan shift 2

Shudhanshu Gupta Student Expert 23rd Jan, 2020
Hello.
You can calculate your approximate rank by using the formula:
(100-your total percentile score)*869010/100.
Approximate rank at 20 percentile would be : 695,208 which is not so good rank, at this percentile you have very degraded chances of having good colleges with good branch even you have degraded chances
241 Views

i scored 62.73 percentile in jee main 2020. How to calculate my score. Am i eligible to get in ssn college

rajaman9300 Student Expert 18th Jan, 2020

Hello Preethi

You can calculate your rank by using this formula. 874469 are the number of candidates appeared for the January exam. So rank formula is (100- your total score) * 874469 / 100.

Considering General category, your percentile is pretty less hence i will suggest you to focus on

2308 Views

hi i got a nta score of 78 in total in jee mains 2020, what does this mean is it a good score

Pratham Meghani 18th Jan, 2020
Dear Aspirant

Nta score of 78 means that 78 percentage of students are left behind you in competition of jee mains exam .But for Qualifying Jee mains and eligible for Jee advanced the percentile above 85 is considered to be safe score .
So you need extra hard work and
57 Views

My NTA Score in JEE 2020 is 75.624 (Physics : 43.21, Chemistry : 66.03, Maths : 88.74) Please advise me of teh chances of getting admission to NIT (kerala) or in any otehr NITs in Gneral or OBC Category ...Thanks...

jishua thomas 25th Jan, 2020

Hello aspirant....

For general category as per expected cutoff for this year it is about 89.75 percentile for the jee mains to qualify for the advanced examination. for obc it is 74.31 to qualify. for admission in nit calicut, kerala you need a percentile of 95 plus.. hope you try

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