A student, who got 94.62 percentile in jee mains 2020, belongs to OBC can get into NIT AP in ECE branch
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For your percentile, your rank can be calculated using this formula-
(100- percentile)*number of students appeared/100
That will be in range 46750- 64550
For this rank your OBC rank will be more than 10000.
Last year the closing rank for ECE was 6035 for HS quota.
So, it seems it is difficult to get ECE. You can check other possible branch from this link https://engineering.careers360.com/articles/jee-main-cutoff-for-nit-andhra-pradesh
Hope it helps
First we need to calculate your expected rank which can be calculated by using the formula given below:
(100-your total percentile score)*869010/100.
Here 869010 is the number of candidate appeared for the January session of exam.
So your approximate rank would be: 46,752.
Remember it will be your all India rank if we do not consider any category wise rank.
Now if we go with the previous year record of NIT Andhra Pradesh, as you did not mention your state so I am considering it for both home state and other state so for both in OBC Category the cutoff generally goes under 9.8k which cognate that you have degraded chances of getting admission in NIT Andhra Pradesh.
for predicting more colleges you can use our college predictor tool from the below link:
Best of luck.
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