hello,i score 27.39 in BE./B Tech in JEE examination so am i eligible for vnit ?
Its difficult to predict actual rank or JEE advanced qualify marks. you may calculate your expected rank by this formula
To Calculate the rank for B. Tech:
So Rank Formula is (100 - your total score) X 1200000/100.
But Your predicted JEE Main AIR rank for 2020 is
772046-812680
At this Score or Rank You didn't get admissions in VNIT
I hope you will increase your nta score in April and take admissions in nit or iit
Hope this helps! All The Best!!
Feel free to ask if you have any more queries
Dear Aspirant
Sorry to disappoint you but ,To get vnit nagpur at this score is too difficult
A formula is given by National Testing Agency to calculate rank in Jee mains .The formula is No of Candidates appeared in session /100*(100- Nta score ).
So the no of candidates apperared in exam were 869010 .So your rank will be 630988
If the no of students in April session changes to 120000 then rank can vary and will be accordingly to the formula
120000/100*(100-Nta score )
To get vnit nagpur your rank should be within 7000 and then you can easily get vnit nagpur .
Try your best in April attempt and score best than January session of jee mains.
You can also use college predictor to check chances of getting admiited in particular Colleges -
Thanks
All the very best
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