I have scored 94.4 percentile in jee main 2020 and I'm from Odisha..can somebody tell me what was the cutoff for IIIT bbsr in jee 2019 for odisha state students?
Hello Aspirant.
As you've mentioned that you've scored 94.4 percentile in JEE mains and assuming you belong to general category, then according to the formula
Rank=(100-percentile)*8690.10
Your rank would be around 48,660-48,680. Now as you belong to the home state, then considering this factor there are chances of you getting admission in IIIT- Bhuvneshwar but you might not get more demanded branches like CS or IT. You'll be eligible for lower branches only.
Best of luck !