I have scored 94.4 percentile in jee main 2020 and I'm from Odisha..can somebody tell me what was the cutoff for IIIT bbsr in jee 2019 for odisha state students?
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Hello Aspirant.
As you've mentioned that you've scored 94.4 percentile in JEE mains and assuming you belong to general category, then according to the formula
Rank=(100-percentile)*8690.10
Your rank would be around 48,660-48,680. Now as you belong to the home state, then considering this factor there are chances of you getting admission in IIIT- Bhuvneshwar but you might not get more demanded branches like CS or IT. You'll be eligible for lower branches only.
Best of luck !
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