wht will be my general and obc rank with a percentile of 98.6 as per the final number of unique students?
Hi
As per our rank predictor at
With 98.6 percentile,
----------------------------)Your crl/general rank will be around 14322 - 16100 and obc rank around 3.5k -4k
With your rank , you have chances in following nits which are listed below along with their closing rank in 6th round of josaa counselling 2020 under other state -
-----------) National Institute of Technology, Jamshedpur:- ECE:-4737 OBC rank
-----------) National Institute of Technology Patna:- computer science:-4713 obc rank
-----------) National Institute of Technology Agartala:- computer science:- 5828 obc rank
And more
You can check the closing ranks at official website of josaa by going through the link given below
https://josaa.nic.in/Result/Result/currentorcr.aspx
Or
For previous year cut offs of top colleges like NITs, IIITs , you can also refer our page at :-
NITs :- https://engineering.careers360.com/articles/nits-cutoff-for-top-btech-branches
IIITs:- https://engineering.careers360.com/articles/jee-main-cutoff-for-top-iiits
Above prediction has been made considering past year cut off data but closing rank for colleges varies every year depending upon many factors like jee main question paper difficulty, number of students writing the exam etc so
To have a personalised report on your chances of getting a college you can go through our college predictor, it will give you complete list of colleges which you can get on the basis of the category you belong to, your home state, your gender etc, the link for jee main college predictor is provided below
https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer
To help you further,
To give you an idea of qualifying cut off, JEE mains 2020 qualifying CUT OFF percentile to be eligible for jee advanced is given below for different category
>>>> General :- 90.3765335
>>>> GEN-EWS :- 70.2435518
>>>> OBC-NCL :- 72.8887969
>>>> SC :- 50.1760245
>>>> ST :- 39.0696101
>>>> PwD :- 0.0618524
You can check the same at our page the link is provided below
https://engineering.careers360.com/articles/jee-main-cutoff
Thankyou
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