94 per centile arch is enough for not Goa
Deepak, you can calculate your expected JEE Mains paper 2 rank for the January session using the following formula:
(100-your total percentile) x 112679/100
So with 94 percentile, your rank would be around 6760.
Also, if the number of students increases to 1.5 lakh in the April session, the formula for rank calculation would change to:
(100-your total percentile) x 150000/100
Hence your expected rank in this case would be around 9000.
With your percentile, it will be difficult to get into the NITs or CFTIs as they require a rank below 5000 for admission. Although you can get a seat through state level counselling in NIT Hamirpur or NIT Raipur if you are eligible for Home State quota for these colleges.
You can go to the below link to find the cutoff rank for admission in BArch in NITs or CFTIs for the years 2016 to 2019: https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning/amp
You can also go through our college predictor given below to check which colleges you are eligible for:
All the best.
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