How much marks are required to get Computer Science in DTU in Jee mains 2020 September because the competition is relatively high?
DTU Delhi reports its cut off and merit list for different courses to get a confirmation in UG and PG programs each year. There are around 2 departments and colleges in DTU Delhi for which cutoff will be resolved dependent on the reservation categories and the seat accessibility. DTU Delhi profoundly and gives you the valid adjust shrewd cut information dependent on different sources. Here you will get DTU Delhi 2019 shorts, from first slice off to last cut off for every one of the 2 departments/universities and their courses.
For CSE cutoff rank is 11564 in the 2019 where as in 2018 cutoff rank is 9194.
In 2019 the cut off was as follows for admission to CSE in DTU
- General: 5896
- EWS: 11798
- OBC: 44546
- SC: 77286
- ST: 223920
Outside Delhi region
- General: 1418
- EWS: 3124
- OBC: 5822
- SC: 25375
- ST: 49944
You have not mentioned your category and domicile. You need to score the minimum cut off rank to get admission in DTU and cut off changes every year depending on total number of candidates applied, difficulty of exam, number of seats available etc. We cannot predict the exact marks but a safe score in between 150-220 marks depending on your category. In January session 869010 candidates appeared and for September session 12,00,000 candidates are expected to appear in JEE Main so yes, there are chances of high competition.
We have JEE Main knockout package to help you with your preparation, you may check the details here JEE Main Knockout