I got 90.99 percentile in jee mains 2019...can i get admission in VNIT Nagpur if I'm from bihar and obc category... For cs branch

Helloo..

The formula to calculate the approximate rank is :
(100-percentile)*874469/100.

If we implement your percentile in the formula your predicted rank will be around 78,790.

You have no or very little chance of getting the seat in VNIT Nagpur. Not to worry you will be having one more chance in April and I request you to improve your percentile so that you can get the seat.

For details about closing ranks in VNIT Nagpur please visit the link;
https://www.google.com/amp/s/engineering.careers360.com/articles/jee-main-cutoff-for-vnit-nagpur

All the best..

Hii vaibhav

You don't  have enough percentile to get any of the branch in VNIT nagpur although you are an OBC candiadate. The last closing rank for metallurgy was around 12k in obc. And rank will be not be even close to it, as i have told you earlier. And definitely you will not get CSE.

But you can prepare for jee main in april and get good rank to get in VNIT nagpur.

Hope it helps!