i have 96.2 in jee main january session .With homestate reservation ,what all courses in NIT calicut am i eligible?

Hii

For your percentile your rank can be calculated using this formula-

(100- percentile)*number of students appeared/100

That will be in range 33400-45600.

Let me tell you about the possible branches there for this rank

Civil engineering  37950

Production and Industrial engineering 42435

Biotechnology 43053

Material  science 42155

Check other cutoff here https://engineering.careers360.com/articles/jee-main-cutoff-for-nit-calicut

Hope it helps

Hello student you can calculate and get your rank easily by using this formula.
100 - (your total percentile) 869010 /100
In your case your rank must be around 33022.
With this rank you can get admission in Biotechnology engineering, Materials science and engineering, production engineering, civil engineering at NIT CALICUT.
Cut off vary every year on various factors like the level of question in the entrance examination and total number of applicants in that examination.
For more updates refer to the link mentioned below
https://engineering.careers360.com/articles/jee-main-cutoff-for-nit-calicut

Feel free to comment if you have any doubt
Good luck